Question

I’m getting a frustrating MySql syntax error in my code below. The actual error is:

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘ JOIN storetable ON pricelist.storecode = storetable.storecode JOIN itemlist ON’ at line 9″

Additional info: This code based on Google Maps Php/MySql example: http://code.google.com/apis/maps/articles/phpsqlsearch.html

I was able to get this code to work fine before I tried to add the JOIN statements.

$query = sprintf("SELECT storetable.storeaddress, 
                         storetable.storename, 
                         storetable.lat, 
                         storetable.lng,
                         ( 3959 * acos( cos( radians('%s') ) * 
                         cos( radians( storetable.lat ) ) *                              cos(radians(storetable.lng)  - radians('%s') ) + 
                         sin( radians('%s') ) * sin( radians( storetable.lat ) ) ) ) AS distance 
                    FROM pricelist 
                  HAVING distance < 25 
                ORDER BY distance 
                   LIMIT 0 , 20,
                    JOIN storetable ON pricelist.storecode = storetable.storecode
                    JOIN itemlist ON pricelist.upccode = itemlist.upccode",
                 mysql_real_escape_string($latitude),
                 mysql_real_escape_string($longitude),
                 mysql_real_escape_string($latitude));

Answer 1

JOINs were in the wrong place – they come after the FROM clause, before the WHERE clause – Use:

$query = sprintf("SELECT storetable.storeaddress, 
                         storetable.storename, 
                         storetable.lat, 
                         storetable.lng,
                         ( 3959 * acos( cos( radians('%s') ) * 
                         cos( radians( lat ) ) * cos( radians( lng ) - radians('%s') ) + 
                         sin( radians('%s') ) * sin( radians( lat ) ) ) ) AS distance 
                    FROM pricelist 
                    JOIN storetable ON pricelist.storecode = storetable.storecode
                    JOIN itemlist ON pricelist.upccode = itemlist.upccode
                  HAVING distance < 25 
                ORDER BY distance 
                   LIMIT 0, 20",
                 mysql_real_escape_string($latitude),
                 mysql_real_escape_string($longitude),
                 mysql_real_escape_string($latitude));