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Home/ Questions/Q 670801
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:18:13+00:00 2026-05-14T00:18:13+00:00

I’m getting a javascript error. It has to do with this section of code:

  • 0

I’m getting a javascript error.

It has to do with this section of code:

/*
 * Activate jQuery
 */
$(document).ready(function() {          

/*
 * Show hidden field when 'Other' selected from dropdown
 */
$.listHidden = { 
    '6' : $('.referrer_other')
};
$('#referrer_select').change(function() { 
    // hide all
    $.each($.listHidden, function() { 
        this.hide(); 
    });
    // show current
    $.listHidden[$(this).val()].slideDown(250);
}).change();    

});

The code works like this. The form has a dropdown asking “How did you find us?” If the user selects ‘other’, which is an <option> with value=6, a text input field .referrer_other becomes visible.

Javascript is currently reporting that: '$.listHidden[...] is null or not an object'. It’s an error that appears in IE. I found this code on the internet somewhere. Is there a way to fix it, or should I look for something else?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:18:14+00:00Added an answer on May 14, 2026 at 12:18 am

    The problem is that $.listHidden["0"] doesn’t exist. If all you need to do is show other, I’d change all that code to this:

    $(function() {
      $('#referrer_select').change(function() { 
        if($(this).val() == '6')
          $('.referrer_other:hidden').slideDown(250);
        else
          $('.referrer_other:visible').slideUp();
      }).change(); 
    });
    

    Here’s what it’s doing: on change, this simply looks if the option is “other” and if .referrer_other is not already shown, shows it…if the option is not other, then it hides .referrer_other if it’s still visible.

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