Question

Im getting an error with my SQL queries in PHP. I have tried multiple queries, and have also tired using the PHP code that phpMyAdmin generates. Can anyone help me with this?

Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ”sample_table’ LIMIT 0, 30′ at line 1

Here is the PHP code:

//Connect to server
 $connect = mysql_connect("localhost", "root", "");
if (!$connect) {
    die('Not connected : ' . mysql_error());
}

//Connect to DB
$db_selected = mysql_select_db("testing", $connect);
if (!$db_selected) {
    die ('Can\'t use foo : ' . mysql_error());
}

$sql = "SELECT `Name` FROM `sample_table` LIMIT 0, 30 ";

//Query DB table
$sqlQuery = mysql_query($sql, $connect);
if (!$sqlQuery) {
    die('Invalid query: ' . mysql_error());
}

//fetch the results / convert the results into an array
while($rows = mysql_fetch_array($sqlQuery, MYSQL_NUM)) //this is happening
{   
    $name = $rows['name'];
    $age = $rows['age'];
    $ID = $rows['ID'];

    echo "$name<br/>$age<br/>$ID<br/>";
}

mysql_close($connect);

Here is a screenshot of the phpMyAdmin table that I have created. There are a number records in this table.

Answer 1

Change this:

$sql = "SELECT Name FROM 'sample_table' LIMIT 0, 30 ";

into this:

$sql = "SELECT `Name` FROM `sample_table` LIMIT 0, 30 ";

Notice that I’ve changed the ' into `.

By the way, the echo syntax should look like this:

 echo $name."<br/>".$age."<br/>".$ID."<br/>";