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Home/ Questions/Q 4256104
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T05:18:31+00:00 2026-05-21T05:18:31+00:00

I’m getting better at regex, but I’m still having some trouble… I’m trying to

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I’m getting better at regex, but I’m still having some trouble… I’m trying to extract a value from inside of a set of parentheses using regex. The problem I am having is when this set is preceded by an open parenthesis.

Here are some examples:

'x(1)'.match(/\((.+?)\)/)[1] // returns "1" as expected
'\)(1)'.match(/\((.+?)\)/)[1] // returns "1" as expected

The character before parentheses can be anything, including another open parenthesis

'\((1)'.match(/\((.+?)\)/)[1] // returns "(1", but I only want "1"

This is only a snippet of the string, so this portion is already split out.

Any help would be appreciated!

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  1. Editorial Team
    Editorial Team
    2026-05-21T05:18:32+00:00Added an answer on May 21, 2026 at 5:18 am

    Based on that data set, the easiest thing to do would probably just be to add a quantifier to the open paren, eg:

    /\(+(.+?)\)/

    This way it matches any consecutive number of open parens leading up to what you want to capture, but must at least have one paren immediately preceeding the next part of the match. Example on rubular here. Note though: As I allude to below, this will capture open parens within the grouping that are delimited by other characters (ridgerider provides an example with ( (stuff)) in the comments below, similar would be something like (1(1). It is not explicitly clear from your sample if this is desired behavior, but if not then see below.

    Operating under the assumption that you aren’t going to need to capture a ( anywhere (i.e. you only want the innermost matching parens), you can explicitly make sure you don’t match the ( character anywhere in your group if you use [^(]+? instead of .+?. It’s certainly a more strict alternative, though. You can see that one on rubular here. To reiterate, though: this wouldn’t allow the ( character anywhere within the group, which may or may not be valid in other data you’re working with beyond this sample. You could also further refine this to [^()]+. The full regex would then be either /\(([^(]+?)\)/ or /\(([^()]+)\)/ (I believe these are semantically equivalent, but I probably haven’t covered all corner cases, the latter is the “safest” by means of being the most strict).

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