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Home/ Questions/Q 7722681
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T04:14:43+00:00 2026-06-01T04:14:43+00:00

I’m getting content from a textarea (which besides simple text may include html markup),

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I’m getting content from a textarea (which besides simple text may include html markup), and try to parse it and replace all occurences of “[File:#xx#]” with a string contained in an array.
So, lets say the contents of the textarea is in var html.
I do the following:

html = html.replace(/\[File:#(.*)#\]/g, 
                    function($0, $1){ return furls[$1]; });

everything works fine when the contents the text area are like this:

<img src="[File:#111#]" alt="image1" />
<img src="[File:#222#]" />

but when there is no line break between 2 elements witch have attribute with [File:#xx#] value, then the problem appears.
So, given this as the textarea’s value:

<img src="[File:#111#]" alt="image1" /><img src="[File:#222#]" />

seems like it matces the first img’s [File:#111# but closes it not with the first bracket, rathen than the second one’s. so, what gets replaced is all this:
#]" alt="image1" /><img src="[File:#222

What is wrong with my regular expression? How can i prevent this look-ahead from happening and stop at the first closing bracket?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-01T04:14:46+00:00Added an answer on June 1, 2026 at 4:14 am

    Well the correct regex for your case would be:

    /[File:#[\w]+#]/g
    

    Why is this the case?

    Because in your regex:

    The . Matches any character, except for line breaks if dotall is false.

    The * Matches 0 or more of the preceeding token. This is a greedy match, and will match as many characters as possible before satisfying the next token.

    And in the regex i’ve provided:

    The \w Matches any word character (alphanumeric & underscore).

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