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Home/ Questions/Q 8939691
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T10:52:25+00:00 2026-06-15T10:52:25+00:00

I’m getting this warning warning C4309: ‘initializing’ : truncation of constant value and when

  • 0

I’m getting this warning

warning C4309: 'initializing' : truncation of constant value

and when I try to execute my dll it only sends 4 bytes instead of the 10 bytes.
What could be wrong?

Here is my code:

int WINAPI MySend(SOCKET s, const char* buf, int len, int flags)
{

    cout << "[SEND:" << len << "] ";

    for ( int i = 0; i < len; i++ ) {
        printf( "%02x ", static_cast<unsigned char>( buf[i] ) );
    }

    printf("\n");

    //causing the warning:
    char storagepkt[] = {0x0A, 0x00, 0x01, 0x40, 0x79, 0xEA, 0x60, 0x1D, 0x6B, 0x3E};

    buf = storagepkt;
    len = sizeof(storagepkt);

    return pSend(s, buf, len, flags);
}

UPDATE

int (WINAPI *pSend)(SOCKET s, const char* buf, int len, int flags) = send;
int WINAPI MySend(SOCKET s, const char* buf, int len, int flags);

UPDATE

As suggested I tried memcpy:

memcpy((char*) buf, storagepkt, sizeof(storagepkt));

UPDATE

unsigned char storagepkt[] = {0x0A, 0x00, 0x01, 0x40, 0x79, 0xEA, 0x60, 0x1D, 0x6B, 0x3E};

Fixed it.

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  1. Editorial Team
    Editorial Team
    2026-06-15T10:52:26+00:00Added an answer on June 15, 2026 at 10:52 am

    You’re initializing a buffer of char which is signed. Anything over 0x7f is beyond what it can handle and will be converted to a negative number. The actual data is probably OK and you can ignore the warning, although it would be better to make it unsigned char.

    As for why it’s only sending 4 bytes, that sounds suspiciously like the size of a pointer. Are you sure the code is exactly as you’ve represented it, using an array, rather than a pointer passed to a function? A function doesn’t know the size of an array even when you declare the parameter as an array – you need to pass the size of the array into the function.

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