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Asked: 2026-05-31T21:14:31+00:00

I’m going over the jquery widget here: http://blog.davidpadbury.com/2010/10/11/bdd-testing-of-jquery-plugins-using-jasmine/ The plugin is called like so:

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I’m going over the jquery widget here: http://blog.davidpadbury.com/2010/10/11/bdd-testing-of-jquery-plugins-using-jasmine/

The plugin is called like so:

$('#list').list({'input':$('#new-value')})

So ‘#new-value’ is an input text field. By wrapping $() around ‘#new-value’ it is a jQuery selection.

Inside the widget _create method there is this line:

this.input = $( this.options.input )

this.options.input should be $('#new-value'). It’s already a jQuery object right? Why are they wrapping it within another $( )? What does that do? Can I leave it out?

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1 Answer

  1. Editorial Team

    It is probably implemented, so the selector could be given instead of object as the input option.

    Passing jQuery object into jQuery function changes nothing – the same object is returned. Well, maybe not the same object, but the documentation says about jQuery function:

    It will also accept another jQuery object, effectively returning $(other.get()).

    so it will retrieve DOM objects from jQuery object and pass them again to jQuery function, returning the result.

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