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Home/ Questions/Q 1063161
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T18:44:34+00:00 2026-05-16T18:44:34+00:00

I’m going through Structure and Interpretation of Computer Programs and I’m having a bit

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I’m going through “Structure and Interpretation of Computer Programs” and I’m having a bit of trouble doing one of the exercises ( 2.1 ) . I’m coding in DrRacket in R5RS mode.

here’s my code :

(define (make-rat n d) 
  (let (((c (gcd n d))
         (neg (< (* n d) 0))
         (n (/ (abs n) c))
         (d (/ (abs d) c)))
        (cons (if neg (- n) n) d))))

and here’s the error message DrRacket is giving me:

let: bad syntax (not an identifier and expression for a binding) in: ((c (gcd n d)) (neg (< (* n d) 0)) (pn (/ (abs n) c)) (pd (/ (abs d) c)))

I think I’ve messed up let’s syntax. but I’m not sure how to fix it.

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  1. Editorial Team
    Editorial Team
    2026-05-16T18:44:35+00:00Added an answer on May 16, 2026 at 6:44 pm

    As your edit indicates, you’re using the c identifier prematurely. (Which is why it isn’t working after fixing the syntax issue of the extra parenthesis.) Identifiers in “let” don’t see each other. You’d need to nest your second three lets under the first.

        (let ((c (gcd ...)))
          (let ((...))
            exps ...))
    

    I don’t recall when/if SICP introduces other let forms, but if you are stuck using a lot of nested lets, you can use let* in which each subsequent identifier is in the scope of all the previous. That is, the following two definitions are equivalent:

    (define foo
      (let* ((a 1)
             (b (+ 1 a))
             (c (+ 1 b)))
        (+ 1 c)))
    
    (define foo
      (let ((a 1))
        (let ((b (+ 1 a)))
          (let ((c (+ 1 b)))
            (+ 1 c)))))
    

    The scoping rules of the different let forms can be a bit much for a beginner, unfortunately.

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