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Home/ Questions/Q 228585
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:41:40+00:00 2026-05-11T19:41:40+00:00

I’m going to extend the existing std::map class and add a new function to

  • 0

I’m going to extend the existing std::map class and add a new function to it:

template<typename key_type, typename value_type>
class CleanableMap : public Cleanable, public std::map<key_type, value_type> 
{
    CleanableMap(const CleanableMap& in); //not implemented
    CleanableMap& operator=(const CleanableMap& in); //not implemented
public:
    CleanableMap() {}
    CleanableMap(const std::map<key_type, value_type>& in) { *this = in; }
    virtual ~CleanableMap() {}
    std::map<key_type, value_type>& operator=(const std::map<key_type, value_type>& in)
    {
        *((std::map<key_type, value_type>*)this) = in;
        return *this;
    }
};

I’ve got a copy constructor and assignment operator such that I can simply assign an existing std::map of the same type to my new map:

CleanableMap<DWORD, DWORD> cm;
std::map<DWORD, DWORD> stdm;
cm = stdm;

The problem is, the compiler is complaining with an error that doesn’t make sense — I’ve explicitly coded for what it’s complaining about:

1>c:\dev\proj\commonfunc.cpp(399) : error C2679: binary '=' : no operator found which takes a right-hand operand of type 'std::map<_Kty,_Ty>' (or there is no acceptable conversion)
1>        with
1>        [
1>            _Kty=DWORD,
1>            _Ty=DWORD
1>        ]
1>        c:\dev\proj\templates.h(245): could be 'CleanableMap<key_type,value_type> &CleanableMap<key_type,value_type>::operator =(const CleanableMap<key_type,value_type> &)'
1>        with
1>        [
1>            key_type=DWORD,
1>            value_type=DWORD
1>        ]
1>        c:\dev\proj\templates.h(250): or       'std::map<_Kty,_Ty> &CleanableMap<key_type,value_type>::operator =(const std::map<_Kty,_Ty> &)'
1>        with
1>        [
1>            _Kty=unsigned long,    <--- where did it come up with that?
1>            _Ty=std::pair<const DWORD,DWORD>,  <--- where did it come up with that?
1>            key_type=DWORD,
1>            value_type=DWORD
1>        ]
1>        while trying to match the argument list '(CleanableMap<key_type,value_type>, std::map<_Kty,_Ty>)'
1>        with
1>        [
1>            key_type=DWORD,
1>            value_type=DWORD
1>        ]
1>        and
1>        [
1>            _Kty=DWORD,
1>            _Ty=DWORD
1>        ]

There ‘could be’ it mentions on line 245 doesn’t make sense — there is no assignment operator like that (well, it’s private. Removing it completely doesn’t change anything).

The ‘could be’ it mentions on line 250 is the assignment operator that I defined, but it was somehow deduced some other non-matching template types. Where did it get those??

Help!!! 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T19:41:40+00:00Added an answer on May 11, 2026 at 7:41 pm

    Adding onto Neil’s answer.

    One concrete reason you should not be deriving from std::map is that it does not have a virtual destructor. This means you simply cannot guarantee any resources you allocate as a part of your map will be freed during the destruction of your implementation via a std::map pointer.

    std::map<int,int>* pMap = GetCleanableMap();
    ...
    delete pMap; // does not call your destructor
    
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