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Home/ Questions/Q 727309
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:33:11+00:00 2026-05-14T06:33:11+00:00

I’m grabbing lines from a text file and sifting line by line using regular

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I’m grabbing lines from a text file and sifting line by line using regular expressions. I’m trying to search for blank lines, meaning nothing or just whitespace.

However, what exactly is empty space? I know that whitespace is \s but what is a line that is nothing at all? null (\0)? newline (\n)?

I tried the test harness in the Java tutorial to try and test to see what an empty space is but no luck so far.

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:33:11+00:00Added an answer on May 14, 2026 at 6:33 am

    An empty string "" is a string. It’s not null. It doesn’t have any character, not even \0 (which is just a character in Java, i.e. it’s not a string terminator (JLS 10.9)).

    The following are all true:

    "" != null
    "" instanceof String
    "".contains("")
    

    The following are true exclusively for an empty string:

    "".matches("")
    "".matches("^$")
    "".length() == 0
    "".isEmpty()
    

    This is also true for an empty string as well as all other strings containing only whitespaces:

    "".matches("\\s*");
    

    This is because * is zero-or-more repetition of a pattern. Zero repetition of a whitespace is an empty string.

    The following is also true for all strings containing only whitespaces:

    s.trim().isEmpty()
    

    Further discussions

    I notiched that \s* detects one or more whitespaces. How do I make it so that it detects only whitespace? For example "test test" would be invalid?

    \s* matches zero or more whitespaces, and "test test".matches("\\s*") is false.

    However, you can find \s* in "test test", just as you can find it in any string, because \s* can match the empty string, and all strings contains("").

    Figured it out… ^\s*[^a-zA-Z0-9\W]|^$

    [^a-zA-Z0-9\W] doesn’t really make any sense, and in fact "_".matches("^\\s*[^a-zA-Z0-9\\W]|^$").

    Perhaps the confusion is because matches in Java needs to match the whole string (i.e. as if you’ve surrounded the entire pattern with ^ and $), so you can drop the anchors for matches but you’d need it for, say find. The proper regex for such methods would then be "^\\s*$", with the anchors explicitly included.

    The following is an excerpt from cletus’s original answer (which is now deleted):

    Pattern p = Pattern.compile("^\\s*$", Pattern.MULTILINE);
    Matcher m = p.matcher(fileString);
    while (m.find()) {
      ...
    }
    

    The Pattern.MULTILINE allows ^ and $ to also match line terminators within fileString.

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