Question

I’m having a bit of trouble with this one, as basic as it may be. I have a simple form with name, email, comments, etc. that outputs itself to one php page, but I want to have a link that sends it to a second page, for example:

<label for="name">Name:</label><input type="text" name="name" size="20" />

Goes to a second page (second.php) with this code and prints it just fine:

print "<div>Thank you, $name.</p></div>";

But if I try to send $name to a third page (third.php) using similar code it shows up like this:

Thank you, $name.

With the actual variable and not what was stored in $name.

I feel like I’m missing one tiny little thing but I’m not sure what it is. I used this:

$name = $_POST['name'];

To bring it to second.php and this to bring it to third.php:

print 'Click <a href="third.php? name=' . $name . '">here</a> to proceed.';

Just to see if it would get the same information from second.php, but I don’t think it works that way. Is there something else I should be doing on the third page? I have a feeling it’s something incredibly insignificant but as I’m learning, I just can’t quite get a grasp on it.

Answer 1

You can do it this way.

when you declare

$name = $_POST['name'];

you can use in a header to pass this variable

if(isset($_POST['btnname']))
{
header('Location: second.php?name='.$name);
}

The in your second php

you can get it by this way

 Thank you, <php echo $_GET['name']; ?>

Or if you want it to be available to all pages use session

$_SESSION['name'] = $_POST['name'];

=D