Question

I’m having a hard time figuring out how to do this if statement. I want to do this:

IF (the function has only 1 argument
AND $1 is a directory (in the current
folder)) OR IF (the function has 2
arguments AND $1 is NOT a directory ) THEN

....

END

Sorry if it’s not very clear,

Thanks in advance

Answer 1

You pretty much said what is needed in the question:

if [ $# = 1 -a -d "$1" ] || [ $# = 2 -a ! -d "$1" ]
then
    ...
fi

You can use other operators too – that will work in Bourne shell, let alone Korn or other POSIX shells (assuming that $# works correctly in a function – which it does in Bash).

fun()
{
    if [ $# = 1 -a -d "$1" ] || [ $# = 2 -a ! -d "$1" ]
    then echo "Pass ($1, $#)"
    else echo "Fail ($1, $#)"
    fi
}

fun $HOME
fun $HOME abc
fun $HOME/xyz abc
fun /dev/null