Question

I’m having a hard time putting some queries together.

SELECT `part_num`, COUNT(`part_num`) AS `total` 
    FROM `job_sheet` 
    WHERE `qty`!=0 AND `completion`=1 
    GROUP BY `part_num` 
    ORDER BY `total` DESC 
    LIMIT 10

This basically pulls up the most common part number and it shows how many times it appears in the ‘total’ variable. I also limited to the top 10 part number in this case. These parts number also have a quantity column ‘qty’ that shows how many parts there are:

part_num | qty 

1001     | 1000
1004     | 200 
1003     | 360 
1001     | 1000
1001     | 1000

In this case my first statement would show that part number 1001 would appear three times, item number 4 would appear once etc., etc. My issue is that I would like to add up the qty column along with my statement in order to show that item 1001 appears 3 times with a ‘qty’ sum of 3000.

Any ideas on how to do this ?

Answer 1

You don’t need to use DISTINCT as you are already using a GROUP BY.

To show the sum you simply need to add the field with the SUM() function.

SELECT part_num, COUNT(part_num) AS total, SUM(qty) as total_qty 
    FROM job_sheet 
    WHERE qty!=0 AND completion=1 
    GROUP BY part_num 
    ORDER BY total DESC 
    LIMIT 10;