Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1068717
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T20:19:22+00:00 2026-05-16T20:19:22+00:00

I’m having a little trouble with an sql query. Which is why I hope

  • 0

I’m having a little trouble with an sql query. Which is why I hope some of you will be able to help me.

I’ve got an query that selects the latest entry from each relational id but i want to select the latest where the status is different. The table looks like this.

+-----------+-------------+------+-----+-------------------+----------------+
| Field     | Type        | Null | Key | Default           | Extra          |
+-----------+-------------+------+-----+-------------------+----------------+
| id        | int(11)     | NO   | PRI | NULL              | auto_increment |
| kid_id    | int(11)     | NO   |     | NULL              |                |
| status    | varchar(50) | NO   |     | NULL              |                |
| timestamp | timestamp   | NO   |     | CURRENT_TIMESTAMP |                |
+-----------+-------------+------+-----+-------------------+----------------+

And my current query looks like this.

SELECT * 
            FROM (
                SELECT * 
                FROM actions 
                AS a
                WHERE date(timestamp) = curdate() 
                AND timestamp = (
                    SELECT max(timestamp) 
                    FROM actions 
                    AS b
                    WHERE a.kid_id = b.kid_id
                    )
                )
            AS c
            ORDER BY kid_id

And the result looks like this:

id  kid_id  status  timestamp
54  1   Kommet  2010-09-15 00:14:51
57  2   Gået    2010-09-15 00:17:58
56  3   Kommet  2010-09-15 00:15:00

The problem is that where kid_id equals 2 I would like to see the latest entry where status = “Kommet”….

I want the 2 newest records from each kid. The first record where status = “Kommet” and the second where status = “Gået”

In advance thank you very much for your help… It’s really appreciated 🙂

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T20:19:22+00:00Added an answer on May 16, 2026 at 8:19 pm

    If you’re not to bothered about getting the id, then you could run the following:

    SELECT kid_id, status, MAX(`timestamp`) as `timestamp`
    FROM actions
    WHERE DATE(`timestamp`) = CURDATE()
    GROUP BY kid_id, status
    

    If you needed the id, tou couldn’t just add to the SELECT list though, as the GROUP BY will pull one of the matching ids to display here, not neccessarily the one that matches the MAX(timestamp).

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

No related questions found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.