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Home/ Questions/Q 9019231
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T04:43:37+00:00 2026-06-16T04:43:37+00:00

I’m having a problem in the where clause of my INNER JOIN subquery. I’m

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I’m having a problem in the where clause of my INNER JOIN subquery. I’m receiving a unknown column error for M.idMembre. I’ve tried using the table name instead of the alias but I get the same issue. I’ve also tried removing the WHERE clause from the subquery and adding this condition in the ON clause after the subquery. However, I’m having the same issue either way. I feel it’s something obvious I’m missing here.

SELECT DISTINCT M.`idMembre` ,  `couponsTypes`.`maxCouponType` 
FROM membres AS  `M` 
INNER JOIN (
SELECT idMembre, MAX( coupons.`idType` ) AS  `maxCouponType` 
FROM coupons
WHERE coupons.`idMembre` = M.`idMembre` 
GROUP BY idMembre
) AS  `couponsTypes` 
ON M.`idMembre` = couponsTypes.`idMembre`
ORDER BY maxCouponType DESC 

Let me know if you need more information.

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  1. Editorial Team
    Editorial Team
    2026-06-16T04:43:39+00:00Added an answer on June 16, 2026 at 4:43 am

    You are not allowed to reference outer tables in a subquery in a join clause. One way to solve this is by doing a group by in the subquery based on the join condition:

    SELECT DISTINCT M.`idMembre`, `couponsTypes`.`maxCouponType`
    FROM membres AS `M` 
    INNER JOIN
    (SELECT idMembre, MAX(coupons.`idType`) AS `maxCouponType`
       FROM coupons
       GROUP BY idmembre
    ) `couponsTypes`
    ON couponstypes.idMembre = M.idMember
    ORDER BY maxCouponType DESC
    

    But, you don’t need the membres table at all. Although referenced in the outer select, it is equivalent to the member id in the coupons type table. So, you can write your query as:

    SELECT idMembre, MAX(coupons.`idType`) AS `maxCouponType`
    FROM coupons
    GROUP BY idmembre
    ORDER BY 2 DESC
    

    This is probably the simplest and most efficient way formulation.

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