Question

I’m having a problem trying to getline lines from a .txt file. I used a similar algorithm in another piece of code and document with seemingly no issues (= all lines were printed). However, when I try to the same thing using getline (As usual) i get my string line = “”. My lines are not empty and I have a pre-test to check if the file opens, which it does. Below is a function from my program. Could anyone provide some help? Thanks!

I am trying to run case ‘A’

  void Database::LoginMenu(string code)
  {
    cout << endl;
    cout << "Thank You for Login In, Would You Like To..." << endl;
    cout << "====================================================" << endl;
    cout << "A. View your registration information" << endl;
    cout << "B. Search for others" << endl;
    cout << "C. Search for Upcoming" << endl;
    cout << "D. Enter the Database" << endl;

    char choice, YN;

    cout << endl;
    cout << "Please choose an option: ";
    cin >> choice;

    switch(choice)
    {
    case 'A':
        {
            ifstream myfile("RegistrationInfo.txt");
            string line;
            if(myfile.is_open())
            {   
                while(!myfile.eof())
                {
                    getline(cin, line);

                    if(line[5] == ':')
                    {
                        line = line.substr(7, line.size());
                    }
                    if(line == code)
                    {
                        while(!line.empty())
                        {
                            cout << line << endl;
                        }
                    }
                }
            }   
            cout << "Would you like to return to the menu? (Y/N)";
            cin >> YN;      

            if(YN == 'Y')
            {
                LoginMenu(code);
            }

            myfile.close();
        }
        break;
    case 'B':
        {
            ifstream filein("RegistrationInfo.txt");
            string temp, YN, enteredInfo;
            int n = 0;

            cout << "Who do you wish to search for? :";
            cin >> enteredInfo;

            while(!filein.eof())
            {
                getline(cin, temp);
            }
        }
        break;
    case 'C': upcomingComps();
        break;
    case 'D': DatabaseMenu();
        break;
    }
  }

Here are a few lines form my txt file.

• CCode: abd50896
• Names: TomMullen NicoleLaBerge
• Compt: Rutgers DanceSport 2012
• Level: Newcomer
• Dance: Tango Waltz Quickstep Rumba ChaCha Jive

Answer 1

Suggest the call use myfile as the first argument, instead of cin — getline(myfile, line) — because cin represents stdin, which is not the file you opened.