Question

I’m having a problem with my python script.

It’s printing massive amounts of data on the screen, and I would like to prevent all sorts of printing to screen.

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Edit:

The library I’m using is mechanize, and it’s printing a LOT of data on screen.

I have set these to false with no luck!

br.set_debug_redirects(False)
br.set_debug_responses(False)
br.set_debug_http(False)

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Any ideas?

Help would be amazing and very much appreciated!

Answer 1

(Based on your 2nd edit)

If you don’t want to disable all output, you can try to be specific to mechanize itself. http://wwwsearch.sourceforge.net/mechanize/ provides a snippet, which I’ve modified (though I’m not sure if it will work):

import logging
logger = logging.getLogger("mechanize")
# only log really bad events
logger.setLevel(logging.ERROR)

---

When you print something it goes to the screen through the sys.stdout file. You can change this file to any other file (eg, a log file you open) so that nothing is printed to the screen:

import sys
# save the old stdout so you can print later (do sys.stdout = OLD_STDOUT)
OLD_STDOUT = sys.stdout
sys.stdout = open("logfile.txt", 'w')

Of course, if you’re talking about some library that you’re calling, it may be printing to sys.stderr. Luckily, you can do the exact same thing for this one (continuing from above):

OLD_STDERR = sys.stderr
sys.stderr = open("errorLog.txt", 'w')

Now if, for some reason, you want to completely ignore stdout (or stderr) and never see it again, you can define your own file-like classes that simply discard the objects:

class Discarder(object):
    def write(self, text):
        pass # do nothing
# now discard everything coming out of stdout
sys.stdout = Discarder()

And, to add to the din of possible solutions, here is a solution that works in Unix shells:

# discards all input (change /dev/null to a file name to keep track of output)
python yourScript.py > /dev/null