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Home/ Questions/Q 6361109
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:44:02+00:00 2026-05-24T23:44:02+00:00

I’m having a problem with the method declaration for a nested class template. I

  • 0

I’m having a problem with the method declaration for a nested class template.
I have something like this:

template <typename T>
class HashTrie
{
    template <typename Y>
    class Entry
    { // members and methods here
    };

    template <typename U>
    class Node
    { // members and methods here
    };

     // members and methods here
}

The following seems to work without a problem:

template <typename T>
template <typename Y>
HashTrie<T>::Entry<Y> HashTrie<T>::Entry<Y>::someMethod() {
    //...
}

However, this does not:

template <typename T>
template <typename U>
std::map<char, HashTrie<T>::Node<U> > HashTrie<T>::Node<U>::anotherMethod() {
// ...
}

I get the following error on GCC

./HashTrie.h:389: error: type/value mismatch at argument 2 in template parameter list for ‘template<class _Key, class _Tp, class _Compare, class _Alloc> class std::map’
./HashTrie.h:389: error:   expected a type, got ‘(HashTrie::Node < <expression error>)’
./HashTrie.h:389: error: template argument 4 is invalid
./HashTrie.h:389: error: expected unqualified-id before ‘>’ token

I tried adding a typename, but that doesn’t seem to help

template <typename T>
template <typename U>
std::map<char, typename HashTrie<T>::Node<U> > HashTrie<T>::Node<U>::anotherMethod() {
// ...
}

results in…

./HashTrie.h:389: error: template argument 2 is invalid
./HashTrie.h:389: error: template argument 4 is invalid
./HashTrie.h:389: error: expected unqualified-id before ‘>’ token

icpc says:

./HashTrie.h(389): error: template parameter "HashTrie<T>::Node [with T=T]" may not have a template argument list
    std::map<char, typename HashTrie<T>::Node<U> > HashTrie<T>::Node<U>::newNodeMap() {

I’m not really sure what to do here, and had a hard time finding any similar problems across the web. Any help would be appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:44:03+00:00Added an answer on May 24, 2026 at 11:44 pm

    Say this:

    template <typename T>
    template <typename U>
    std::map<char, typename HashTrie<T>::template Node<U> > HashTrie<T>::Node<U>::foo()
    {
    }
    
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