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Home/ Questions/Q 6375053
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:33:53+00:00 2026-05-25T01:33:53+00:00

I’m having a strange problem with the following code works. Map<String, Object> map =

  • 0

I’m having a strange problem with the following code works.

Map<String, Object> map = new HashMap<String, Object>();

for(Entry<String, Object> entry : map.entrySet()) {
   // 
}

while the code below does not compile.

Map map = new HashMap();

for(Entry entry : map.entrySet()) {  // compile error here
   // 
}

Any clues?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:33:54+00:00Added an answer on May 25, 2026 at 1:33 am

    Burt has the right reason and Henning expands on it in the comments. When referencing a member of a raw type, generics don’t come into play at all, even generics that don’t rely on the type parameter.

    As an example, this should compile just fine…

    public class DataHolder<T> {
        public List<T> ts;
        public List<String> strings = new ArrayList<String>();
    }
    
    //...
    DataHolder holder = new DataHolder();
    holder.strings.add(Integer.valueOf(42));
    

    …even though T doesn’t need to be mapped to a concrete type to know what the type of strings should be.

    This is true for generic member methods as well, which is what you are running into. entrySet returns the raw type Set, not Set<Entry>, even though the type parameters would not need to be known to return a Set<Entry>. The behaviour is documented in the Java Language Specification, section 4.8:

    The type of a constructor (§8.8), instance method (§8.8, §9.4), or non-static field (§8.3) M of a raw type C that is not inherited from its superclasses or superinterfaces is the erasure of its type in the generic declaration corresponding to C. The type of a static member of a raw type C is the same as its type in the generic declaration corresponding to C.

    It’s a very “gotcha” rule.

    See also

    Java Class Generics and Method Generics conflicts

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