Question

I’m having a tough time figuring out how to have a select list drive what is returned in a table. Scenario, there are a list of projects, pending what project your user has access to a subset of items are returned.

Here is some code:

query:

$q = "SELECT DISTINCT projectid, projectname FROM projects where active=1";

select list construction:

//variable for projects list select list name
$dropdown = "Projects Lists \n <select name=\"ProjectsLists\">";

//loop results
while ($row = mysql_fetch_assoc($result)){
$dropdown .= "\r\n<option value='{$row['projectid']}'>{$row['projectname']}</option>";
}//end while

$dropdown .= "\r\n</select>";

echo $dropdown;

Then what i’d like to do is display items returned from a query that needs to be run when the select list is select:

$s_query = "SELECT contentname, contentlocation FROM projectscontent WHERE projectname=<select list value>";

I’m having trouble figuring out if i can capture the selected value. If so, how? I thought i could maybe do $_GET['selectlistname']; but i don’t think that is right.

Answer 1

you have to use jquery event .change() this will help you for what you want.
For example:

1. Add an id in you select options
   like $dropdown = "Projects Lists \n <select id=\"mylist\" name=\"ProjectsLists\">";

now with jquery use something like this:

$('#mylist').change(
  //provide you selected value
  var proName = $(this).val();

  //call ajax
  $.ajax({
   url: 'queryPage.php',
   data: 'proName=' + proName,
   success: function(data){
      $('#result').html(data);
   }
  });
);

queryPage.php:

//$_REQUEST['proName'] provide you select product name
$productname = mysql_real_escape_string( $_REQUEST['proName'] );

// Now start your query
$s_query = "SELECT contentname, contentlocation FROM projectscontent 
            WHERE projectname='$productname' ";

now start to run the query and echo the result here on the same page, this will return the data to the page from where you call queryPage.php.