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Home/ Questions/Q 922161
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T18:59:01+00:00 2026-05-15T18:59:01+00:00

I’m having a very hard time trying to do something very simple. Here’s the

  • 0

I’m having a very hard time trying to do something very simple. Here’s the code:

        if(data == 'success') {

            alert('foo');

        } else {

            alert(data);

        }

I’ve simplified it, but that’s all that’s necessary to understand what’s going on. the variable ‘data’ is a result of an AJAX call, if that makes any difference. The problem is that it always goes to the ‘else’ statement and it alerts ‘success’, which it shouldn’t if it goes to the ‘else’. Any idea what’s going on here?

EDIT: Here’s the full AJAX code in jQuery:

$.post("/manage_sites.php", {before:before, edit:after}, function(data){

        if(data == success) {

            alert('blah');

        } else {
            alert(data);
        }
    });

And then in the PHP response:

...code....
$update = mysql_query("UPDATE users SET feeds = '$afterFeed' WHERE username = '$name'") or     die("Query Failed");

if($update) {

    echo  'success';  //this is the 'string' that is being given to 'data'
}
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  1. Editorial Team
    Editorial Team
    2026-05-15T18:59:01+00:00Added an answer on May 15, 2026 at 6:59 pm

    You can fix it on the client side using $.trim() like this:

    if($.trim(data) == 'success') {
    

    Or, a better approach would be removing the new-line coming from the server-side, probably an erroneous new-line in your PHP somewhere, check before or after the <? ?> block, this is most often where they crop up.

    Or, just exit after outputting your content, like this:

    if($update) {
      echo 'success';
      exit();
    }
    
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