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Home/ Questions/Q 6901331
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T07:39:36+00:00 2026-05-27T07:39:36+00:00

I’m having difficulties to display data from mysql database to PHP generated table. Interesting

  • 0

I’m having difficulties to display data from mysql database to PHP generated table. Interesting that query shown below runs fine in SQL, but when I try to wrap it in PHP, it displays empty table without giving any errors.

SELECT city.name, cinema.name, whattime, whichdate
FROM city, cinema, relationship
WHERE cinema.city = city.id
AND cinemaid = cinema.id
ORDER BY whichdate

Here is the PHP code:

<?php
$usr = "admin";
$pwd = "";
$db = "dbname";
$host = "localhost";

$con = mysql_connect($host, $usr, $pwd) or die(mysql_error());
mysql_select_db($db) or die(mysql_error());

$sql = "select city.name, cinema.name, whichdate, whattime ";
$sql .= "from city, cinema, relationship ";
$sql .= "where cinema.city = city.id ";
$sql .= "and cinemaid = cinema.id ";
$sql .= "order by whichdate";
$query = mysql_query($sql, $con) or die(mysql_error()); 

echo "<table id='premiere'>";
echo "<tr> <th>CITY</th> <th>CINEMA</th> <th>DATE</th> <th>TIME</th></tr>";
 while($result = mysql_fetch_array( $query )) {
    echo "<tr><td>"; 
    echo $result['city.name'];
    echo "</td><td>"; 
    echo $result['cinema.name'];
    echo "</td><td>";
    echo $result['relationship.whichdate'];
    echo "</td><td>";
    echo $result['relationship.whattime'];
    echo "</td></tr>";
}
echo "</table>";    
?>

Any help would be appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T07:39:37+00:00Added an answer on May 27, 2026 at 7:39 am

    Your fetched array will not include the table names as array keys, only the column names (as in $result['whichname'])

    Use column aliases for city.name and cinema.name to differentiate them.

    $sql = "select city.name AS cityname, cinema.name AS cinemaname, whichdate, whattime ";
    //--------------------^^^^^^^^^^^^^^^------------^^^^^^^^^^^^^^^
    $sql .= "from city, cinema, relationship ";
    $sql .= "where cinema.city = city.id ";
    $sql .= "and cinemaid = cinema.id ";
    $sql .= "order by whichdate";
    

    Then, instead of:

    while($result = mysql_fetch_array( $query )) {
        echo "<tr><td>"; 
        echo $result['city.name'];
        echo "</td><td>"; 
        echo $result['cinema.name'];
        echo "</td><td>";
        echo $result['relationship.whichdate'];
        echo "</td><td>";
        echo $result['relationship.whattime'];
        echo "</td></tr>";
    }
    

    use only the column names (or aliases) as array keys:

    while($result = mysql_fetch_array( $query )) {
        echo "<tr><td>"; 
        echo $result['cityname'];
        echo "</td><td>"; 
        echo $result['cinemaname'];
        echo "</td><td>";
        echo $result['whichdate'];
        echo "</td><td>";
        echo $result['whattime'];
        echo "</td></tr>";
    }
    
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