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Home/ Questions/Q 3977058
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T04:52:41+00:00 2026-05-20T04:52:41+00:00

I’m having issues with jQuery selectors (again). I’m sure this is really simple but

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I’m having issues with jQuery selectors (again). I’m sure this is really simple but I seem to be strugling.

This is the selector that’s causing me problems. The variables ClassImg and TitleImg all seem to be ok.

$('img [class=' + ClassImg + '][attr="1"][title=' + TitleImg + ']').attr("src", "../graphics/stars/FullStar.png");

I’ve been fiddling about with it here: http://jsfiddle.net/PottyMonster/aYr8e/

Thanks in advance for your help.

Dan

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  1. Editorial Team
    Editorial Team
    2026-05-20T04:52:42+00:00Added an answer on May 20, 2026 at 4:52 am

    Some helpful notes:

    1. You can use img.' + ClassImg the class selector instead of the [attr] selector for class names.
    2. I assume you mean alt=1
    3. Since you are using jquery look at using .hover() as it will help produce less Unobtrusive javascript.
    4. If you use Unobtrusive javascript wrap your event handlers in $(document).ready(function(){}); or simply $(function(){});

    From looking at what your example it appears like you want to highlight the stars on hover.
    Since you have the stars under a <p> tag you can call parent on the <img> and than use the :lt() selector to select the <img/> stars less than the current star you are hovering over. Putting this all together ends up with something like the following:

    $("img").hover(function() {
        var AltImg = $(this).attr("alt");
        $(this).parent().children(":lt(" + AltImg + ")").attr("src", "http://www.sweetashoney.co.uk/graphics/stars/FullStar.png");
    },
    function() {
        $('img[name=FeedbackStar]').attr("src", "http://www.sweetashoney.co.uk/graphics/stars/EmptyStar.png");
    });
    

    Example on jsfiddle.

    Hope this helps! If I missed the mark let me know and I will revisit.

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