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Home/ Questions/Q 8968047
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T17:22:57+00:00 2026-06-15T17:22:57+00:00

I’m having more and more trouble while trying to make an easy excercise. i’m

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I’m having more and more trouble while trying to make an easy excercise.
i’m trying to delete all eventual starting charater ” ” in a string.

Example:space-space-space50(i cannot figure it because this forum remove extra space)
result:50

Here’s the code …

            char c=textToShow.getText().toString().charAt(1);
    int i=1;
    while (c == ' '){
        textToShow.setText(textToShow.getText().toString().substring(i));
    //New char
        i++;
    c=textToShow.getText().toString().charAt(i);
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T17:22:58+00:00Added an answer on June 15, 2026 at 5:22 pm

    You have the right idea, but your implementaion is off.
    First

    char c=textToShow.getText().toString().charAt(1);
    

    should start at 0, that is how the indexes are made.

    The int is properly initialized but is not even really needed. This is because you work with only the beginning of the String.
    However your loop is where things go awry.
    Your substring code is proper, but now, you don’t need to increment i, since you’re modifying the String by shortening it. Also,

    c=textToShow.getText().toString().charAt(i);
    

    Should be c=textToShow.getText().toString().charAt(0); You are still checking the beginning of the String.

    A more efficient implementation using the loop could be:

    char c=textToShow.getText().toString().charAt(0);
    String temp = textToShow.setText(textToShow.getText().toString();
    while (c == ' ' && temp.length > 0)//also check to see if you're accessing an empty string.
    {
      temp = temp.substring (1);
      c = temp.charAt (0);
    }
    textToShow.setText (temp);
    

    Of course, this is for an excersice, if you wanted to do it the right way, you’d use temp.trim();

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