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Home/ Questions/Q 8033805
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T01:49:00+00:00 2026-06-05T01:49:00+00:00

I’m having some difficulty figuring out a regular expression for stripping part of the

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I’m having some difficulty figuring out a regular expression for stripping part of the string within a particular XML tag and replacing it. I have a number of URL paths with variable parts, so I need to find everything between a certain string and the last slash in the URL. For example, I might have tags and URLS that look like this:

<bpoc:resourceMetadataLoc>http://app01/media/images/I//1951-1960_Embark_Object_Photos/1957.59.jpg</bpoc:resourceMetadataLoc>

or

<bpoc:resourceMetadataLoc>http://app01/media/images/CONTEMPORARY/1986-2005/1991.2.jpg</bpoc:resourceMetadataLoc>

The output should look like

<bpoc:resourceMetadataLoc>http://app01/media/Previews/1957.59.jpg</bpoc:resourceMetadataLoc>

This is about as far as I got, but it captures the last slash in the string, and not the second-to-last slash:

(<bpoc:resourceMetadataLoc>http://app01/media/images)+(.*[/])

That regex will capture the following:

<bpoc:resourceMetadataLoc>http://app01/media/images/I//1951-1960_Embark_Object_Photos/1957.59.jpg</

What would I need to add to the regex to exclude the </bpoc:resourceMetadataLoc> bit from the query and then capture everything prior to the last slash in the URL?

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  1. Editorial Team
    Editorial Team
    2026-06-05T01:49:01+00:00Added an answer on June 5, 2026 at 1:49 am

    Because this is XML, there can’t be a (non-escaped) < or > in the URL itself. You can use this to your advantage:

    <bpoc:resourceMetadataLoc>http://app01/media/images[^<]*/([^<]*)
    

    This should capture the last segment (e.g. “1957.59.jpg”) of the URL. It works by greedily matching everything up to the start of the end-of-tag (the first [^<]*), then backtracking to match the nearest (i.e. last) /, then capturing everything after that slash (the ([^<]*)) into group 1 so that you can use it during the replacement step.

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