Question

I’m having some problems generating an AJAX response with PHP. The response should be a associative array with the database values inside. These values are displayed in a selectbox afterwards.

if (isset($_POST['rolle'])) {
    $sql = "SELECT rolle FROM pu_zugriff_rolle ORDER BY rolle ASC";

    $result = mysql_query($sql);

    $result = mysql_fetch_array($result);

    echo json_encode($result);
}

There are several entries stored in the database but I only get the first database value twice as a result. The sql query is definitively not the problem.

I read somewhere the $result = my_sql_array($result); statement is needed to create an assiciative array. If I’m leaving it the statement out, it results in an empty selectbox.

Answer 1

You can do this:

$finalArr = array();

while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $finalArr[] = $row;
}

echo json_encode($finalArr);