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Home/ Questions/Q 737113
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:40:59+00:00 2026-05-14T07:40:59+00:00

I’m having some problems trying to perform a query. I have two tables, one

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I’m having some problems trying to perform a query. I have two tables, one with elements information, and another one with records related with the elements of the first table. The idea is to get in the same row the element information plus several records information.

Structure could be explain like this:

 table [ id, name ]
 [1, '1'], [2, '2']

 table2 [ id, type, value ]
 [1, 1, '2009-12-02']
 [1, 2, '2010-01-03']
 [1, 4, '2010-01-03']
 [2, 1, '2010-01-02']
 [2, 2, '2010-01-02']
 [2, 2, '2010-01-03']
 [2, 3, '2010-01-07']
 [2, 4, '2010-01-07']

And this is want I would like to achieve:

 result [id, name, Column1, Column2, Column3, Column4]

 [1, '1', '2009-12-02', '2010-01-03', , '2010-01-03']
 [2, '2', '2010-01-02', '2010-01-02', '2010-01-07', '2010-01-07']

The following query gets the proper result, but it seems to me extremely inefficient, having to iterate table2 for each column. Would be possible in anyway to do a subquery and reuse it?

SELECT
      a.id,
      a.name,
      (select min(value) from table2 t where t.id = subquery.id and t.type = 1 group by t.type) as Column1,
      (select min(value) from table2 t where t.id = subquery.id and t.type = 2 group by t.type) as Column2,
      (select min(value) from table2 t where t.id = subquery.id and t.type = 3 group by t.type) as Column3,
      (select min(value) from table2 t where t.id = subquery.id and t.type = 4 group by t.type) as Column4
FROM
      (SELECT distinct id
       FROM table2 t
       WHERE (t.type in (1, 2, 3, 4))
             AND t.value between '2010-01-01' and '2010-01-07') as subquery
       LEFT JOIN table a ON a.id = subquery.id
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:40:59+00:00Added an answer on May 14, 2026 at 7:40 am

    You can take the aggregations out into a CTE (common table expression):

    with minima as (select t.id, t.type, min(value) min_value
                    from table2 t
                    where t.type in (1,2,3,4)
                    group by t.id, t.type)
    select a.id, a.name,
           (select min_value from minima where minima.id = subquery.id and minima.type = 1) as column1,
           (select min_value from minima where minima.id = subquery.id and minima.type = 2) as column2,
           (select min_value from minima where minima.id = subquery.id and minima.type = 3) as column3,
           (select min_value from minima where minima.id = subquery.id and minima.type = 4) as column4
    from (select distinct id from table2 t where t.type in (1,2,3,4) and t.value between '2010-01-01' and '2010-01-07') as subquery
         left join a on a.id = subquery.id
    

    Whether this is actually any benefit (or even supported) or not depends on your environment and dataset, of course.

    Another approach:

    select xx.id, a.name, xx.column1, xx.column2, xx.column3, xx.column4
    from (
          select id,
                 max(case type when 1 then min_value end) as column1,
                 max(case type when 2 then min_value end) as column2,
                 max(case type when 3 then min_value end) as column3,
                 max(case type when 4 then min_value end) as column4
          from (select t.id, t.type, min(value) min_value
                from table2 t
                where t.type in (1,2,3,4)
                group by t.id, t.type) minima
          group by id
    ) xx left join a on a.id = xx.id
    order by 1
    
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