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Home/ Questions/Q 3315260
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:19:45+00:00 2026-05-17T22:19:45+00:00

I’m having some problems with HXT , though I suspect it’s just something I’m

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I’m having some problems with HXT, though I suspect it’s just something I’m missing about arrows.

I have an XML structure like

<str name="field1">value</str>
<lst name="field2"><str>value2</str><str>value3</str></lst>

And internal structure like

data XmlData = XmlStr String | XmlList XmlData

Is there a way to collect elements at a step in an arrow?

getXmlData :: IOSArrow XmlTree (String, XmlData)
getXmlData = (getAttrl >>> getChildren >>> getText) &&& 
      ((filterByType "str" >>> getText >>> arr (\x -> XmlStr x))
      <+> (filterByType "lst" >>> getXmlData))
  where filterByType t = isElem >>> hasName t >>> getChildren

The recursive call to getXmlData needs to collect it’s answer and wrap in an XmlList constructor, but I don’t know how to collect terms. Currently I’m accomplishing this with some post processing on the output (collecting on the same name), but I would like a better solution.

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:19:46+00:00Added an answer on May 17, 2026 at 10:19 pm

    In general you can use listA from Control.Arrow.ArrowList to do this. It has type (ArrowList a) => a b c -> a b [c] and is a

    combinator for converting an arrow
    into a determinstic version with all
    results collected in a single element
    list.

    (See my answers here and here for a concrete example.)

    In this specific case you can use the >. combinator with the XmlList constructor as its second argument to accomplish the same thing more concisely.

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