Question

I’m having some trouble searching a SQLite database in my Android app. I use the Search interface to pass the search variable (searchActivity.query) to this:

   //searchActivity.query obtained from: 
   //String query = searchActivity.getStringExtra(SearchManager.QUERY);

   String searchString = "'" + searchActivity.query + "%'";

   //sqlitedb is called via: private SQLiteDatabase sqlitedb;

   Cursor cursor = sqlitedb.query(DATABASE_TABLE, new String[] 
    {"id", "FirstName","LastName"}, 
    "FirstName LIKE " + searchString, null, null, null, null);

    int index_CONTENT = cursor.getColumnIndex(FirstName);

    for(cursor.moveToFirst(); !(cursor.isAfterLast()); cursor.moveToNext()){
        result = result + cursor.getString(index_CONTENT) + "\n";
    }

The problem is that using the “LIKE” statement outputs everything in the database – defeating the purpose of using the Search interface. I’m not too sure where I’m going wrong.

I tried replacing LIKE with “=” except that displayed nothing, even when I was 100% sure the record existed.

Any help would be greatly appreciated!

Thanks in advance,

Joe

UPDATE:
Sorry about the misleading title. I wasn’t passing the search query properly.

Answer 1

Try this,

Cursor cursor = sqlitedb.query(DATABASE_TABLE, new String[] 
    {"id", "FirstName","LastName"}, 
    "FirstName LIKE '"+searchActivity.query+"%'", null, null, null, null);

and let me know what happen..