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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T18:25:40+00:00 2026-05-14T18:25:40+00:00

I’m having some trouble translating my working C# regular expression into JavaScript’s regular expression

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I’m having some trouble translating my working C# regular expression into JavaScript’s regular expression implementation.

Here’s the regular expression:

([a-z]+)((\d+)([a-z]+))?,?

When used on "water2cups,flour4cups,salt2teaspoon" you should get:

[
    ["water", "2cups", "2", "cups"]
    ["flout", "4cups", "4", "cups"]
    ["salt", "2teaspoon", "2", "teaspoon"]
]

… And it does. In C#. But not in JavaScript.

I know there are some minor differences across implementations. What am I missing to get this expression working in JavaScript?

Update

I am using the regex like so:

"water2cups,flour4cups,salt2teaspoon".match(/([a-z]+)((\d+)([a-z]+))?,?/g);
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  1. Editorial Team
    Editorial Team
    2026-05-14T18:25:41+00:00Added an answer on May 14, 2026 at 6:25 pm

    Creating the RegExp

    You haven’t shown how you’re creating your Javascript regular expression, e.g., are you using a literal:

    var rex = /([a-z]+)((\d+)([a-z]+))?,?/;
    

    or a string

    var rex = new RegExp("([a-z]+)((\\d+)([a-z]+))?,?");
    

    If the latter, note that I’ve escaped the backslash.

    Global Flag

    By default, Javascript regular expressions are not global, that may be an issue for you. Add the g flag if you don’t already have it:

    var rex = /([a-z]+)((\d+)([a-z]+))?,?/g;
    

    or

    var rex = new RegExp("([a-z]+)((\\d+)([a-z]+))?,?", "g");
    

    Using RegExp#exec rather than String#match

    Your edit says you’re using String#match to get an array of matches. I have to admit I hardly ever use String#match (I use RegExp#exec, as below.) When I use String#match with your regex, I get…very odd results that vary from browser to browser. Using a RegExp#exec loop doesn’t do that, so that’s what I’d do.

    Working Example

    This code does what you’re looking for:

    var rex, str, match, index;
    
    rex = /([a-z]+)((\d+)([a-z]+))?,?/g;
    str = "water2cups,flour4cups,salt2teaspoon";
    
    rex.lastIndex = 0; // Workaround for bug/issue in some implementations (they cache literal regexes and don't reset the index for you)
    while (match = rex.exec(str)) {
        log("Matched:");
        for (index = 0; index < match.length; ++index) {
            log("&nbsp;&nbsp;match[" + index + "]: |" + match[index] + "|");
        }
    }
    

    (The log function just appends text to a div.)

    My output for that is:

    Matched:
      match[0]: |water2cups,|
      match[1]: |water|
      match[2]: |2cups|
      match[3]: |2|
      match[4]: |cups|
    Matched:
      match[0]: |flour4cups,|
      match[1]: |flour|
      match[2]: |4cups|
      match[3]: |4|
      match[4]: |cups|
    Matched:
      match[0]: |salt2teaspoon|
      match[1]: |salt|
      match[2]: |2teaspoon|
      match[3]: |2|
      match[4]: |teaspoon|
    

    (Recall that in Javascript, match[0] will be the entire match; then match[1] and so on are your capture groups.)

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