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Home/ Questions/Q 9206547
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T00:11:56+00:00 2026-06-18T00:11:56+00:00

I’m having this interesting ArrayIndexOutofBounds exception. The code is this: int m = 0;

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I’m having this interesting ArrayIndexOutofBounds exception.

The code is this:

int m = 0;
while (scan.hasNextInt())
{
    intArray[m++] = scan.NextInt();
}

I’m merely scanning a bunch of integers into an array, but I always get an ArrayIndexOutofBounds error. I thought my int m was already initialized to zero?

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  1. Editorial Team
    Editorial Team
    2026-06-18T00:11:57+00:00Added an answer on June 18, 2026 at 12:11 am

    inputString.length() returns the number of characters in the string. it does not necessarily correspond to the number of numbers in your string.You will want to add another condition to your while statement to ensure that m doesn’t get larger than intArray.length. Also you probably want to step through the code with a debugger to determine exactly when the array runs out of space.

    Since java arrays are fixed size, if you don’t know what the size of your input is going to be, you should instead use ArrayList<Integer> to store your input.

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