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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:06:59+00:00 2026-05-14T04:06:59+00:00

I’m having trouble getting my head around algorithm analysis. I seem to be okay

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I’m having trouble getting my head around algorithm analysis. I seem to be okay identifying linear or squared algorithms but am totally lost with nlogn or logn algorithms, these seem to stem mainly from while loops? Here’s an example I was looking at:

Algorithm Calculate(A,n) 
Input: Array A of size n 
t←0 
for i←0 to n-1 do 
   if A[i] is an odd number then 
      Q.enqueue(A[i]) 
   else 
      while Q is not empty do 
         t←t+Q.dequeue() 
while Q is not empty do 
  t←t+Q.dequeue() 
return t 

My best guess is the for loop is executed n times, its nested while loop q times making NQ and the final while loop also Q times resulting in O(NQ +Q) which is linear?

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:06:59+00:00Added an answer on May 14, 2026 at 4:06 am

    First, lets assume that Q is initially empty.

    Q will only grow at most at the same rate of the execution of the main loop. For example, if we have iterated over 3 times so far, then Q is at most 3 elements large. So when the inner while loop executes, it can at most only execute up to the current value of ‘i’. This means that the inner loop isn’t a true case on n^2 (which isn’t something you claimed anyway). However, since Q can at most only be ‘i’ elements large, thus we know that O(calculate) <= O(2N). And since in O notation we really don’t care about scalars, then it is O(N).

    Unless I’m wrong 🙂

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