Question

I’m having trouble in getting the pointer of a function that I access through pointers:

double *d = &(this->c1->...->myFunc();

does not work, myFunc() is declared as double.
Is there a way of doing this?

Answer 1

If you mean that you want a pointer to the value returned by myFunc, then you can’t: it’s a temporary, and will be destroyed at the end of the expression.

If you need a pointer, then you’ll also need a non-temporary value to point at:

double value = this->c1->...->myFunc();
double * d = &value;

Or are you saying that you want a pointer to the function? That’s a different type to double*:

// get a member-function pointer like this
double (SomeClass::*d)() = &SomeClass::myFunc;

// call it like this
double value = (this->c1->...->*d)();

Or are you saying that you want something you can call like a simple function, but bound to some object this->c1->...? The language doesn’t directly support that, but C++11 has lambdas and a bind function for that sort of thing:

// Bind a function to some arguments like this
auto d = std::bind(&SomeClass::myFunc, this->c1->...);

// Or use a lambda to capture the object to call the member function on
auto d = [](){return this->c1->...->myFunc();};

// call it like this
double value = d();