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Home/ Questions/Q 9249033
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T10:05:36+00:00 2026-06-18T10:05:36+00:00

Im having trouble setting a variable as part of a function, im sure its

  • 0

Im having trouble setting a variable as part of a function, im sure its down the syntax more than anything, what im trying to do is use a if/else statement and as part of it, to return a variable $Bname.

But im not sure how to set it.

My function is as follows

 function bestPriceFunc($var1, $var2) {
      if ($var1 < $var2) {
          return $var1;
          $Bname = 'will';
          return $Bname;

      } else {
          return $var2;
          $Bname = 'Lad';
          return $Bname;
      }
  }

is this the correct way to do it or could i just write return $Bname = 'Lad';. Ive tried both but i getting an undefined variable error when i load the page

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T10:05:37+00:00Added an answer on June 18, 2026 at 10:05 am

    You can only use return once per function as it terminates the function the first time it is executed.

    Try the following or if you don’t need to return $var1 and $var2, simply remove those lines.

    <?php
    function bestPriceFunc($var1, $var2) {
        if ($var1 < $var2) {
            $Bname = 'will';
            return array($var1, $Bname);
    
        } else {
            $Bname = 'Lad';
            return array($var2, $Bname);
        }
    }
    
    $var = bestPriceFunc(3, 4);
    $bnameoutput = $var[1];
    ?>
    
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