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Home/ Questions/Q 9240655
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T08:13:40+00:00 2026-06-18T08:13:40+00:00

I’m having trouble understanding the following line: result = (status!=None and off or on)

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I’m having trouble understanding the following line:

result = (status!=None and "off" or "on")

Now when this is called, only status has been assigned a value (the result of a regular expression search). However, after this command, result takes the value of “on” or “off”.

To my untrained eye, this just looks like a comparison. How is this assignment happening?

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  1. Editorial Team
    Editorial Team
    2026-06-18T08:13:41+00:00Added an answer on June 18, 2026 at 8:13 am

    From the documentation:

    The expression x and y first evaluates x; if x is false, its value is returned; otherwise, y is evaluated and the resulting value is returned.

    The expression x or y first evaluates x; if x is true, its value is returned; otherwise, y is evaluated and the resulting value is returned.

    Furthermore, any non-empty string is considered to be "true" when it appears in a boolean context.

    With this, we can tackle your question.

    Due to operator precedence rules, the following:

    status != None and "off" or "on"
    

    is equivalent to:

    (status != None and "off") or "on"
    

    The first part, status != None and "off" evaluates to:

    • False if status is None;
    • "off" otherwise

    The entire expression, (status != None and "off") or "on" evaluates to:

    • "on" if status is None;
    • "off" otherwise.

    An arguably more Pythonic way to write this statement is:

    result = "on" if status is None else "off"
    
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