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Home/ Questions/Q 8531465
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T09:29:19+00:00 2026-06-11T09:29:19+00:00

I’m having trouble understanding the order in which an || is executed in Jquery/Javascript.

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I’m having trouble understanding the order in which an || is executed in Jquery/Javascript.

If I have this:

  someVar = $el.attr("one") || options.two || "three";

it sets someVar to “three” when both $el.attr("one") and options.two are not defined.

I need to add another condition to this statement, like so:

  someVar = $el.attr("one") || options.two || options.extra == "true" ? undefined : "three";

So this should say:

If neither '$el.attr("one")' or 'options.two' are defined, check if 'options.extra == true', if it’s true, set to 'undefined', otherwise set to 'three'.

However, I’m always getting undefined even if I set $el.attr("one") and I don’t understand why?

Can anyone tell me what is wrong in my logic?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-11T09:29:20+00:00Added an answer on June 11, 2026 at 9:29 am

    I think you must put some parenthesis:

    someVar = $el.attr("one") || options.two || (options.extra == "true" ? undefined : "three");
    

    in fact your own code is read as:

    someVar = ($el.attr("one") || options.two || options.extra == "true") ? undefined : "three";
    
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