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Home/ Questions/Q 9178251
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T17:30:30+00:00 2026-06-17T17:30:30+00:00

I’m having trouble with a query I’m trying to write in oracle. Basically I

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I’m having trouble with a query I’m trying to write in oracle.

Basically I want to get the count of two tables that have the same provider list. I can run the query individually but not sure how to do it in one shot.

Here’s a example:

SELECT name, COUNT(name)
FROM   table1
group by name

This gives me a list of names and a count beside them. If I run the same command but on table2(changing the from statement), it works fine. What I want to do is have a query that takes count from table1 and substracts it from count from table2.

How can I do it? I have tried to do nested selects and so on but can’t seem to get it to work.

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  1. Editorial Team
    Editorial Team
    2026-06-17T17:30:31+00:00Added an answer on June 17, 2026 at 5:30 pm

    One option assuming that the name values in both tables are identical would be

    SELECT t1.name, t2.cnt - t1.cnt diff
      FROM( SELECT name, COUNT(name) cnt 
              FROM table1
             group by name ) t1,
          ( SELECT name, COUNT(name) cnt 
              FROM table2
             group by name ) t2
     WHERE t1.name = t2.name
    

    If you want to handle the case where one table has a name that the other doesn’t but you don’t know which table has the extra name (and assuming that you want to say that the other table has a cnt of 0 for that name)

    SELECT coalesce(t1.name, t2.name) name, 
           nvl(t1.cnt, 0 ) t1_cnt,
           nvl(t2.cnt, 0 ) t2_cnt,
           nvl(t2.cnt,0) - nvl(t1.cnt,0) diff
      FROM( SELECT name, COUNT(name) AS cnt
              FROM table1
             group by table1.name ) t1
          full outer join
          ( SELECT name, COUNT(name) AS cnt
              FROM table2
             group by table2.name ) t2
          on( t1.name = t2.name )
    

    which you can see in this SQLFiddle

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