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Home/ Questions/Q 7088935
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T07:51:42+00:00 2026-05-28T07:51:42+00:00

I’m having trouble with getting the records for the following TABLE id | holiday_From

  • 0

I’m having trouble with getting the records for the following

TABLE
id | holiday_From | holiday_To
1  | 2012-01-02   | 2012-01-03
1  | 2012-01-11   | 2012-01-16
1  | 2012-01-08   | 2012-01-22
1  | 2012-01-29   | 2012-01-30
1  | 2012-01-08   | 2012-01-11

I’m trying to get occurrences of holidays for a given month – i.e.

BETWEEN "2012-01-01" AND "2012-01-31"

there is a similar post but im unable to tweak it for my needs

RESULT
day (within range) | count() //number of ppl on holiday
DATE               | 3

for e.g.

SAMPLE OUTPUT
2012-01-02 | 1
2012-01-03 | 1
2012-01-08 | 2
2012-01-09 | 2
2012-01-10 | 2
2012-01-11 | 3
2012-01-12 | 2
2012-01-13 | 2
2012-01-14 | 2
2012-01-15 | 2
2012-01-16 | 2
......

In other words I am trying to get how many times a record is found for a specific date. I.e. how many people are on holiday on the 1st, 2nd 3nd etc.

Not every day is in the TABLE for each month

Any ideas?

p.s. this is what i have already (my shot in the dark)

SELECT h.holiday_From, h.holiday_To, COUNT( * )
FROM holiday h
JOIN holiday ho ON h.holiday_From
BETWEEN DATE( "2012-01-01" )
AND IF( DATE( "2012-01-31" ) , DATE( "2012-01-31" ) , DATE( "2012-01-01" ) )
GROUP BY h.holiday_From, h.holiday_To
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T07:51:42+00:00Added an answer on May 28, 2026 at 7:51 am

    Please, do not be scared :))

    Based on generate days from date range

    select d.everyday, count(*) from (select @rownum:=@rownum+1, date('2012-01-01') + interval (@rownum-1) day everyday from
    (select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
    (select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
    (select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
    (SELECT @rownum:=0) r WHERE @rownum < DAY(LAST_DAY('2012-01-01'))) d, tablename tbl WHERE d.everyday>=tbl.hFrom AND d.everyday<tbl.hTo GROUP BY d.everyday
    

    Result:

    2012-01-02  1
    2012-01-08  2
    2012-01-09  2
    2012-01-10  2
    2012-01-11  2
    2012-01-12  2
    2012-01-13  2
    2012-01-14  2
    2012-01-15  2
    2012-01-16  1
    2012-01-17  1
    2012-01-18  1
    2012-01-19  1
    2012-01-20  1
    2012-01-21  1
    2012-01-29  1
    

    ps: I renamed columns to hFrom and hTo

    pps: updated variant for the range of dates

    select d.everyday, count(*) from (select @rownum:=@rownum+1, date('2012-01-01') + interval (@rownum - 1) day everyday from
    (select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
    (select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
    (select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
    (SELECT @rownum:=0) r WHERE @rownum <= DATEDIFF('2012-01-11','2012-01-01')) d, `test` tbl WHERE d.everyday BETWEEN tbl.hFrom AND tbl.hTo GROUP BY d.everyday
    

    Updated – number 2 was missing from all the unions. it should not significantly affect anything.

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