Question

I’m having trouble with some PHP since yesterday, looked through the web and had the stupid feeling that I’m missing something important.

Using mysql_fetch_object usually, tried it with mysql_fetch_array though (did not help). Here’s the part of the code which gives me an headache:

public static function get_datacenter_by_id($id) {
$result = mysql_query("SELECT COUNT(rack.id) AS Racks, COUNT(device.id) AS Devices, COUNT(card.id) AS Cards, COUNT(port.id) AS Ports 
          FROM datacenter, rack, device, card, port, location, building 
          WHERE location.id = building.location_id AND
          building.id = datacenter.building_id AND
          datacenter.id = '.$id.' AND
          rack.id = device.rack_id AND
          device.id = card.device_id AND
          (card.id = port.card_id1 OR
          card.id = port.card_id2)") or die ("Error in query: ".mysql_error());

$array = array();

while($row = mysql_fetch_object($result)) {
    $array[] = array($row->Racks, $row->Devices, $row->Cards, $row->Ports);                     
}

return $array;
}

$array is used in another .php file, but using print_r $array already shows you, that the array stays empty (0). I’m quite sure that the error appears in this block of code, could “COUNT (x) AS y” be at fault?

PS: The MySQL Query works, tested it via Workbench before. I’d appreciate some good adivce! 🙂

Have a nice day!

Answer 1

Isn’t this as simple as:

$result = mysql_query("SELECT COUNT(rack.id) AS Racks, COUNT(device.id) AS Devices,     COUNT(card.id) AS Cards, COUNT(port.id) AS Ports 
      FROM datacenter, rack, device, card, port, location, building 
      WHERE location.id = building.location_id AND
      building.id = datacenter.building_id AND
      datacenter.id = '" . $id . "' AND
      rack.id = device.rack_id AND
      device.id = card.device_id AND
      (card.id = port.card_id1 OR
      card.id = port.card_id2)") or die ("Error in query: ".mysql_error());

Note the modification from ‘.$id.’ to ‘” . $id . “‘. Your query is looking for a data centre ID of ‘.$id.’.