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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:31:06+00:00 2026-05-11T21:31:06+00:00

I’m implementing a singleton class as follows: static Singleton* _singletonInstance; @implementation Singleton +(void)initialize {

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I’m implementing a singleton class as follows:

static Singleton* _singletonInstance;

@implementation Singleton

+(void)initialize
{ 
    _singletonInstance = [[Singleton alloc] init]; 
}

+(Singleton*)instance
{
    return(_singletonInstance);
}

initialize only gets called the first time someone calls instance. I then have a method that I can call to set up some instance variables. So it ends up looking like this.

_singleton = [Singleton instance];
[_singleton setupWithParams: blah];

When i get an instance of this singleton inside an object, it works fine the first time; However, after i dealloc and create a new copy of the object that needs an instance of the singleton, i get a BAD ACCESS error when I try to call the setup function.

Just to test things I print out the address of the instance before I make the setup call and both times they report the same address, but when i check the error log for BAD ACCESS call, it lists a completely different memory address.

Does anyone have any ideas why this pointer to the instance seems to look fine when I print it, but when I make a call to it, it is seemingly pointing to random data?

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:31:06+00:00Added an answer on May 11, 2026 at 9:31 pm

    The pointer value looks valid because it used to be, but most likely the memory has been free’d, which is why what it points to looks like random data.

    You’ve acquired one reference with your [[Singleton alloc] init] above, but is there a release somewhere else that might be executing? I bet your code is calling instance, and then release-ing later, even though your code never acquired a reference. And that shouldn’t be necessary for a singleton anyways. Just a guess…

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