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Home/ Questions/Q 3628232
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T23:59:22+00:00 2026-05-18T23:59:22+00:00

I’m implementing a stream insertion operator for a class of mine. I’d like my

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I’m implementing a stream insertion operator for a class of mine. I’d like my class to work with both narrow and wide streams. I’m using a template to allow this kind of behavior — and everything is independent of which stream type is actually used, with the exception of character literals. If it’s a wide string, the character literals need L prepended to the literal, otherwise they do not.

Is there a way to key this sort of thing to the template parameter so that I don’t need to duplicate so much code on this?

(I would prefer to avoid performing narrow-to-wide character or wide-to-narrow character conversions at runtime if possible.)

Example of what I currently have — it’s a template but it won’t work with narrow character streams because of the wide character literals:

template <typename charT, typename traits>
std::basic_ostream<charT, traits>& operator<<(
    std::basic_ostream<charT, traits>& lhs,
    const Process& rhs
    )
{
    lhs << L"Process (0x" << std::setw(8) << std::hex
        << std::setfill(L'0') << rhs.GetId() << L") ";
    lhs << rhs.GetName() << std::endl;
    lhs << L"Command Line: " << rhs.GetCmdLine() << std::endl;
    const std::vector<Thread>& threads = rhs.GetThreads();
    for (std::vector<Thread>::const_iterator it = threads.begin(); 
        it != threads.end(); ++it)
    {
        lhs << L" --> " << *it << std::endl;
    }
    const std::map<void *, Module>& modules = rhs.GetModules();
    for (std::map<void *, Module>::const_iterator it = modules.begin(); 
        it != modules.end(); ++it)
    {
        lhs << L" --> " << it->second << std::endl;
    }
    return lhs;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T23:59:23+00:00Added an answer on May 18, 2026 at 11:59 pm

    If you don’t want the runtime overhead, I think that, although ugly, a macro can help you in this case.

    template <typename T>
    inline const T* select(const char* narrow, const wchar_t* wide);
    
    template <>
    inline const char* select<char>(const char* narrow, const wchar_t* /*wide*/)
    {
        return narrow;
    }
    
    template <>
    inline const wchar_t* select<wchar_t>(const char* /*narrow*/, const wchar_t* wide)
    {
        return wide;
    }
    
    #define doselect(T, str) select<T>(str, L ## str)
    
    template <typename charT, typename traits>
    std::basic_ostream<charT, traits>& operator<<(
        std::basic_ostream<charT, traits>& lhs,
        const Process& rhs
        )
    {
        lhs << doselect(charT, "Process (0x") << std::setw(8) << std::hex
            << std::setfill(charT('0')) << rhs.GetId() << doselect(charT, ") ");
        lhs << rhs.GetName() << std::endl;
        lhs << doselect(charT, "Command Line: ") << rhs.GetCmdLine() << std::endl;
        const std::vector<Thread>& threads = rhs.GetThreads();
        for (std::vector<Thread>::const_iterator it = threads.begin(); 
            it != threads.end(); ++it)
        {
            lhs << doselect(charT, " --> ") << *it << std::endl;
        }
        const std::map<void *, Module>& modules = rhs.GetModules();
        for (std::map<void *, Module>::const_iterator it = modules.begin(); 
            it != modules.end(); ++it)
        {
            lhs << doselect(charT, " --> ") << it->second << std::endl;
        }
        return lhs;
    }
    

    You can probably expand doselect with another nice macro, to further reduce code duplication. i.e. doselect2(" --> ") would automatically expand to doselect(charT, " --> ").

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