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Home/ Questions/Q 8565301
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T17:23:43+00:00 2026-06-11T17:23:43+00:00

I’m interested in trying to see the assembly code for my header file. Playing

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I’m interested in trying to see the assembly code for my header file. Playing around with a simple .cpp file with a dummy main method and compiling it is easy: g++ -S -o prog.exe main.cpp

However, I’m going into header files now. I have a dummy header file func.hpp that just contains a dummy method and now I want to be able to compile it and see its assembly in a .S file. (The main reason for this is so that if I have a more complicated function, maybe I can do some manual optimization in assembly and just build the final executable through g++ -o prog.exe func.S main.cpp.

However, I am not able to find sources that explain this. If I try g++ -S -o func.S func.hpp I get an error message output filename specified twice. Can anyone help me with this?

For reference, here is func.hpp:

int number()
{
    return 0;
}

I’m also trying it out with another hpp file named struct.hpp:

struct Coord
{
    int x;
    int y;
};

Same error for both, but I want to be able to see the assembly for both headers without converting them to .cpp files (because that breaks the meaning of a header file.)

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  1. Editorial Team
    Editorial Team
    2026-06-11T17:23:44+00:00Added an answer on June 11, 2026 at 5:23 pm

    You could force g++ to treat the .hpp file as a C++ source file.

    g++ -x c++ -S -o func.S func.hpp
    

    The reason you get that “output filename specified twice” message is because, when passing a header file to gcc, it will assume you want to compile it into a pre-compiled header. Just as named, this will “compile” the headers, so a *.s file will be generated in the middle. If you pass the -v flag with the original command, you will see that cc1plus is called like:

     /usr/lib/gcc/x86_64-unknown-linux-gnu/4.7.1/cc1plus
         -quiet
         -v 
         -D_GNU_SOURCE 
         func.hpp
         -quiet 
         -dumpbase func.hpp 
         -mtune=generic 
         -march=x86-64 
         -auxbase-strip func.S
         -version 
         -o func.S                # <---
         -o /tmp/ccxEg3J7.s       # <---
         --output-pch= func.S
    

    So indeed -o is specified twice, once from your -o and once from the compiler.

    (Of course the compiler could avoid adding the -o /tmp/ccxEg3J7.s, but the added complexity for this edge case isn’t quite worth it.)

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