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Home/ Questions/Q 3598110
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T20:12:06+00:00 2026-05-18T20:12:06+00:00

I’m iterating over a vector, for each element I look something up in a

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I’m iterating over a vector, for each element I look something up in a table by rowname and copy the return into a different vector. The following code is used for that

gs1 = function(p)
{
output <- character() #empty vector to which results will be forwarded

for (i in 1:length(p)) {
test <- p[i]
index <- which(rownames(conditions) == test)
toappend <- conditions[index,3] #working
output[i] <- toappend
print(paste(p[i],index,toappend,output[i]))
}   
return(output)
}

All it spits out is a vector with numbers….while all other variables seems to contain the correct information (as checked by the print function)
I have the feeling I’m doing something terribly wrong in filling the output vector… I could also use

output <- c(output,toappend)

But that gives me exactly the same, wrong and strange output.

All help is very much appreciated!

Output example

> gs1 = function(p)
+ {
+ output <- character() #empty vector to which results will be pasted
+ 
+ for (i in 1:length(p)) {
+ test <- p[i]
+ index <- which(rownames(conditions) == test)
+ toappend <- conditions[index,3] #working
+ 
+ output <- c(output,toappend)
+ output[i] <- toappend
+ print(paste(p[i],index,toappend,output[i],sep=","))
+ }
+ return(output)
+ }
> ###########################
> test <- colnames(tri.data.1)
> gs1(test)
[1] "Row.names,,,NA"
[1] "GSM235482,1,Glc A,5"
[1] "GSM235484,2,Glc A,5"
[1] "GSM235485,3,Glc A,5"
[1] "GSM235487,4,Xyl A,21"
[1] "GSM235489,5,Xyl A,21"
[1] "GSM235491,6,Xyl A,21"
[1] "GSM297399,7,pH 2.5,12"
[1] "GSM297400,8,pH 2.5,12"
[1] "GSM297401,9,pH 2.5,12"
[1] "GSM297402,10,pH 4.5,13"
[1] "GSM297403,11,pH 4.5,13"
[1] "GSM297404,12,pH 4.5,13"
[1] "GSM297563,13,pH 6.0,14"
[1] "GSM297564,14,pH 6.0,14"
[1] "GSM297565,15,pH 6.0,14"
 [1] "5"  "5"  "5"  "5"  "21" "21" "21" "12" "12" "12" "13" "13" "13" "14" "14" "14"
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T20:12:06+00:00Added an answer on May 18, 2026 at 8:12 pm

    Very likely you’re using a data frame and not a table, and as likely your third column is not a character vector but a factor. And there is no need to write that function, you could easily obtain the wanted by:

    conditions[X,3]
    

    with X being a character vector of row names. eg :

    X <- data.frame(
      var1 = 1:10,
      var2 = 10:1,
      var3 = letters[1:10],
      row.names=LETTERS[1:10]
    )
    > test <- c("F","D","A")
    > X[test,3]
    [1] f d a
    Levels: a b c d e f g h i j
    

    To get it in characters:

    > as.character(X[test,3])
    [1] "f" "d" "a"
    
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