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Home/ Questions/Q 8465391
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T15:01:51+00:00 2026-06-10T15:01:51+00:00

I’m just a simple guy working my way through passing JSON from Android, and

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I’m just a simple guy working my way through passing JSON from Android, and I’ve come across a strange problem.

To better understand how JSON works between PHP and Android, I started by created a Json (OK) passing it to PHP and echoing the exact same file back – just to see what happens.

The problem is that the outgoing JSON.toString() is as follows:
{“Age at Death “:32.5,”Enemy”:”Darius”,”Battles”:[“Issus”,”Arbela”],”Death”:-323}

But the returning JSON.toString() is:
{\”Age at Death \”:32.5,\”Enemy\”:\”Darius\”,\”Battles\”:[\”Issus\”,\”Arbela\”],\”Death\”:-323}

This throws an error when I try to read the Json from PHP. (PS: this is one problem I’ve identified; maybe the source is elsewhere, so don’t let me set you on the wrong track)

Here is my code:

Android:

private void connectToURL() throws UnsupportedEncodingException {
        // TODO Auto-generated method stub
        HttpParams httpParams = new BasicHttpParams();
        HttpClient client = new DefaultHttpClient(httpParams);
        String url = "http://www.this.url.is.correct.php";

        List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
        String hello = myJson.toString();
        nameValuePair.add(new BasicNameValuePair("Json", myJson.toString()));

        HttpPost request = new HttpPost(url);
        request.setEntity(new UrlEncodedFormEntity(nameValuePair));

        //ResponseHandler<String> responseHandler = new BasicResponseHandler();
        try {
            HttpResponse response = client.execute(request);
            HttpEntity entity = response.getEntity();
            String myResponse = EntityUtils.toString(entity);
            showResponse(myResponse);
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }

    private void showResponse(String thisResponse) {
        try {
            JSONObject newJson = new JSONObject(thisResponse);

            viewer02.setText(newJson.toString(2));
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

and here is the PHP (it doesn’t get simpler than this):

<?php

$obj = $_POST['Json'];
//$json = json_encode($obj);
//$string = $json->{'enemy'};

echo $obj;

?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T15:01:53+00:00Added an answer on June 10, 2026 at 3:01 pm

    That happens because of magic quotes options turned on in php.

    IIRC it’s currently deprecated and actually isn’t recommended to use (because of it makes no sense)

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