Question

I’m just beginning in scala and I’m converting some java code into scala and trying to make it nice and functionally elegant.

I have the following code containing a method (getRequiredUploadPathKeys) which gives a union of all of the path keys required by all of the available path templates in MyClass.

trait PathTemplate {
    def getRequiredPathKeys:Set[PathKey]
}

class MyClass(accessPaths:Set[PathTemplate], targetPath:PathTemplate){

    def getAllRequiredPathKeys: Set[PathKey] = {
        val pathKeys = HashSet[PathKey]()
        pathKeys.addAll(targetPath.getRequiredPathKeys)

        for (accessTemp <- accessPaths) {
            pathKeys.addAll(accessTemp.getRequiredPathKeys)
        }
        return pathKeys
    }
}

This method just seems like it could be much more concise in scala. Can anyone point me towards how to get it there?

Thanks,
Paul

Answer 1

Do you mean something like:

def getAllRequiredPathKeys = (accessPaths map { _.getRequiredPathKeys }).flatten ++ targetPath.getRequiredPathKeys