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Home/ Questions/Q 6991825
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T19:33:16+00:00 2026-05-27T19:33:16+00:00

I’m just creating a simple list and then destroying it. And something is going

  • 0

I’m just creating a simple list and then destroying it. And something is going wrong and I always get this annoying error message:

Expression: _BLOCK_TYPE_IS_VALID(pHead->nBlockUse)

Here’s the code:

#include<iostream>
#include<Windows.h>
using namespace std;

struct node
{
    int data;
    node *next;
};

class list
{
protected:
    node *top;
public:
    list()
    {
        top=NULL;
    }

    list random()
    {
        int x=rand()%10;
        for(int i=0; i<x; i++)
        {
            node *p=new node;
            p->data=rand()%100;
            p->next=top;
            top=p;
        }
        return *this;
    }

    void show()
    {
        for(node *p=top; p; p=p->next)
        {
            cout<<p->data<<" ";
        }
        cout<<"\n";
    }

    ~list()
    {
        node *r;
        for(node *p=top; p; p=r)
        {
            r=p->next;
            delete p;
        }
    }
};

int main()
{
    srand(GetTickCount());
    list a;
    a.random().show();
    return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T19:33:16+00:00Added an answer on May 27, 2026 at 7:33 pm

    Your problem is that you are copying your list but you don’t define a copy constructor. The implicitly defined copy constructor will just copy the top pointer so you end up attempting to delete the same chain of nodes twice.

    The copy occurs when you return *this; from your random() member function returning a copy of *this by value.

    The shortest fix would be to make your class non-copyable by declaring a copy constructor and copy assignment operator in the private section of your class.

    private:
        list(const list&);
        list& operator=(const list&);
    

    You can then make random return void, there doesn’t seem to be a good reason why it makes a copy as well.

    You could then just call it like this:

        list a;
        a.random();
        a.show();
    

    The longer fix would be to make your list copyable by making a full implementation of list(const list&) and list& operator=(const list&) that correctly duplicates all the nodes of the source list being copied.

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