I’m just learning about C and got an assignment where we have to translate plain text into morse code and back. (I am mostly familiar with Java so bear with me on the terms I use).
To do this, I have an array with the strings for all letters.
char *letters[] = {
".- ", "-... ", "-.-. ", "-.. ", ".", "..-." etc
I wrote a function for returning the position of the desired letter.
int letter_nr(unsigned char c)
{
return c-97;
}
This is working, but the assignment specifications require the handling of the Swedish umlauted letters åäö. The Swedish alphabet is the same as the English with these three letters in the end. I tried checking for these, like so:
int letter_nr(unsigned char c)
{
if (c == 'å')
return 26;
if (c == 'ä')
return 27;
if (c == 'ö')
return 28;
return c-97;
}
Unfortunately, when I tried testing this function, I get the same value for all of these three: 98. Here is my main, testing function:
int main()
{
unsigned char letter;
while(1)
{
printf("Type a letter to get its position: ");
scanf("%c", &letter);
printf("%d\n", letter_nr(letter));
}
return 0;
}
What can I do to resolve this?
In general encoding stuff is quite complicated. On the other hand if you just want a dirty solution specific to your compiler/platform than add something like this to your code:
It will give hex value for your umlauts. Than just replace in
ifstatements your letter with number.EDIT You say that you are always getting 98 so your scanf got 98 + 97 = 195 = 0x3C from console. According to this table 0x3C is start of UTF8 sequence for common LATIN SMALL LETTER N WITH Something in
Latin1 block. You are onMac OS X?EDIT This is my final call. Quite hackery but it works for me 🙂