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Home/ Questions/Q 9200215
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T22:42:56+00:00 2026-06-17T22:42:56+00:00

I’m just trying a simple callback to get code to execute in order instead

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I’m just trying a simple callback to get code to execute in order instead of asynchronously. This does not work:

function fn1(string, func){
    console.log("hello");
    func();
};

function fn2(){
    console.log("world");
}

fn1("meaninglessString", fn2());

It actually print “world” then “hello” to the console then crashes. But this does:

function fn1(string, func){
    console.log("hello");
    func();
};

fn1("meaninglessString", function(){
    console.log("world");
});

Do I have to always write the callback function code right in the call to fn1 or is there a way to reference an already-written function? Also, is this the best way to be doing this in Node.js if I just want one function to happen after another has finished?

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  1. Editorial Team
    Editorial Team
    2026-06-17T22:42:58+00:00Added an answer on June 17, 2026 at 10:42 pm

    Take a look at your last line:

    fn1("meaninglessString", fn2());
    

    it should be the following instead:

    fn1("meaninglessString", fn2);
    

    Including the parenthesis causes fn2 to be executed immediately.

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