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Home/ Questions/Q 8595169
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T00:22:20+00:00 2026-06-12T00:22:20+00:00

I’m just trying to get a deeper understanding of Objective C. Why do I

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I’m just trying to get a deeper understanding of Objective C.

Why do I have to cast before the call to avoid a warning? Isn’t this a piece of cake for the compiler? Are there any dynamic aspects that I’m missing?

if ([a.class conformsToProtocol:@protocol(P1)])
{
  [(id<P1>)a p1Message];
}

I mean, I understand it in a C/C++ point of view, but after all I’m using an Objective C compiler and I don’t like casts. 🙂

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  1. Editorial Team
    Editorial Team
    2026-06-12T00:22:21+00:00Added an answer on June 12, 2026 at 12:22 am

    If a is a specific type that declares itself at compile time as implementing P1 then you shouldn’t need to cast.

    If a is of type id then you’ll need to cast only if the return type is ambiguous and you’re actually using it, or if it had parameters. That’ll generally mean that there are multiple method signatures for the method name p1Message so the compiler doesn’t know which to expect.

    If a is of some type that doesn’t declare itself as implementing P1 then — unless it separately (and repetitiously) declares p1Message — you’ll get a warning because you’re calling a method that the object may not implement.

    If I had to guess, probably a is declared as being of type id rather than id <P1> (which is more normal for, say, delegates) and you have multiple p1Messages flying around. You might also put the cast in proactively because one day you might have multiple different messages with the same name and someone else that might implement p1Message shouldn’t have to know every other place in the project that somebody uses that method name.

    The compiler can’t induce from the conformsToProtocol: check that it is safe to call p1Message exactly because it’s a dynamic runtime. You may have substituted a different implementation of conformsToProtocol: either at compile time or at runtime, meaning that it isn’t safe to assume that the compiler knows what it does. That call will be dynamically dispatched just like any other.

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