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Home/ Questions/Q 1070679
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T20:36:11+00:00 2026-05-16T20:36:11+00:00

I’m just wondering how I would go about splitting a pixel array (R,G,B,A,R,G,B,A,R,G,B,A,etc.) into

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I’m just wondering how I would go about splitting a pixel array (R,G,B,A,R,G,B,A,R,G,B,A,etc.) into 64×64 chunks. I’ve tried several methods myself but they all seem really over-complex and a bit too messy.

I have the following variables (obviously filled with information):

int nWidth, nHeight;
unsigned char *pImage;

And basically for each chunk I want to call:

void ProcessChunk(int x, int y, int width, int height)

You may be wondering why there is a width and height argument for the processing function, but if the image is not exactly divisible by 64, then there will be smaller chunks at the edge of the image (right-hand side and the bottom). See this image for a better understanding what I mean (red chunks are the chunks that will have <64 width or height arguments).

Chunk diagram

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-16T20:36:12+00:00Added an answer on May 16, 2026 at 8:36 pm

    Just define a MIN() macro to determine the minimum of two expressions, and then it’s easy:

    void ProcessChunk(unsigned char *pImage, int x, int y, int width, int height);
    
    #define MIN(a, b) ((a) < (b) ? (a) : (b))    
    #define CHUNKSIZE 64
    
    void ProcessImage(unsigned char *pImage, int nWidth, int nHeight)
    {
        int x, y;
    
        for (x = 0; x < nWidth; x += CHUNKSIZE)
            for (y = 0; y < nHeight; y += CHUNKSIZE)
                ProcessChunk(pImage, x, y, MIN(nWidth - x, CHUNKSIZE), MIN(nHeight - y, CHUNKSIZE));
    }
    
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